What is (3n^2-4n-15)/(n^2-5n+6) ?

The solution to (3n^2-4n-15)/(n^2-5n+6) is (3n+5)/(n-2)

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simplify (3n^2-4n-15)/(n^2-5n+6)

simplify

\frac{3 n ^{2} - 4 n - 15}{n ^{2} - 5 n + 6}

\frac{3 n + 5}{n - 2}

Solution steps

\frac{3 n ^{2} - 4 n - 15}{n ^{2} - 5 n + 6}

Factor

3 n^{2} - 4 n - 15 : (3 n + 5) (n - 3)

= \frac{( 3 n + 5 ) ( n - 3 )}{n ^{2} - 5 n + 6}

Factor

n^{2} - 5 n + 6 : (n - 2) (n - 3)

= \frac{( 3 n + 5 ) ( n - 3 )}{( n - 2 ) ( n - 3 )}

Cancel the common factor:

n - 3

= \frac{3 n + 5}{n - 2}

2121

\frac{5}{9} - \frac{5}{12}

(- 13 + 4 i) (- 5 - 22 i)

\frac{72 x ^{3}}{6 x ^{2}}

7 x^{2} + 17 x + 10

What is (3n^2-4n-15)/(n^2-5n+6) ?
The solution to (3n^2-4n-15)/(n^2-5n+6) is (3n+5)/(n-2)