What is (2^{-1}-3^{-1})/(2^{-1)+3^{-1}} ?

The solution to (2^{-1}-3^{-1})/(2^{-1)+3^{-1}} is 1/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (2^{-1}-3^{-1})/(2^{-1)+3^{-1}}

simplify

\frac{2 ^{- 1} - 3 ^{- 1}}{2 ^{- 1} + 3 ^{- 1}}

\frac{1}{5}

Decimal Notation

0.2

Solution steps

\frac{2 ^{- 1} - 3 ^{- 1}}{2 ^{- 1} + 3 ^{- 1}}

Simplify

2^{- 1} - 3^{- 1} : \frac{1}{6}

= \frac{\frac{1}{6}}{2 ^{- 1} + 3 ^{- 1}}

Simplify

2^{- 1} + 3^{- 1} : \frac{5}{6}

= \frac{\frac{1}{6}}{\frac{5}{6}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{1 \cdot 6}{6 \cdot 5}

Cancel

\frac{1 \cdot 6}{6 \cdot 5} : \frac{1}{5}

= \frac{1}{5}

x^{3} 28 x^{7} y^{7}

4 y^{2} - 24 x y + 27 x^{2}

\frac{2}{3} \cdot 45

9 \times 9 \times 9 \times 9 \times 9

\frac{27 x ^{- 2} y ^{6}}{3 x ^{5} y ^{2}}

What is (2^{-1}-3^{-1})/(2^{-1)+3^{-1}} ?
The solution to (2^{-1}-3^{-1})/(2^{-1)+3^{-1}} is 1/5