What are the solutions to the equation -2x^2+7x+5=0 ?

The solutions to the equation -2x^2+7x+5=0 are x=-(-7+sqrt(89))/4 ,x=(7+sqrt(89))/4

Find the zeros of -2x^2+7x+5=0

The zeros of -2x^2+7x+5=0 are x=-(-7+sqrt(89))/4 ,x=(7+sqrt(89))/4

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- 2 x^{2} + 7 x + 5 = 0

x = - \frac{- 7 + 89}{4}, x = \frac{7 + 89}{4}

Solution steps

- 2 x^{2} + 7 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 2 ) \cdot 5}{2 ( - 2 )}

7^{2} - 4 (- 2) \cdot 5 = 89

x_{1, 2} = \frac{- 7 \pm 89}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 7 + 89}{2 ( - 2 )}, x_{2} = \frac{- 7 - 89}{2 ( - 2 )}

x = \frac{- 7 + 89}{2 ( - 2 )} : - \frac{- 7 + 89}{4}

x = \frac{- 7 - 89}{2 ( - 2 )} : \frac{7 + 89}{4}

The solutions to the quadratic equation are:

x = - \frac{- 7 + 89}{4}, x = \frac{7 + 89}{4}

\frac{2 x - 5}{x - 2} - 1 > 0

13 = \frac{w - 14}{2}

\frac{5 ( 7 - x )}{2} = \frac{2 ( 2 x - 1 )}{7} + 1

\frac{z - 7}{5} = - 3

6 (8 - 2 n) = 2 n + 6

What are the solutions to the equation -2x^2+7x+5=0 ?
The solutions to the equation -2x^2+7x+5=0 are x=-(-7+sqrt(89))/4 ,x=(7+sqrt(89))/4
Find the zeros of -2x^2+7x+5=0
The zeros of -2x^2+7x+5=0 are x=-(-7+sqrt(89))/4 ,x=(7+sqrt(89))/4