What are the solutions to the equation x^2+10x+25=2 ?

The solutions to the equation x^2+10x+25=2 are x=-5+sqrt(2),x=-5-sqrt(2)

Find the zeros of x^2+10x+25=2

The zeros of x^2+10x+25=2 are x=-5+sqrt(2),x=-5-sqrt(2)

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x^{2} + 10 x + 25 = 2

x = - 5 + 2, x = - 5 - 2

Decimal Notation

x = - 3.58578 \dots, x = - 6.41421 \dots

Solution steps

x^{2} + 10 x + 25 = 2

Move

2

to the left side

x^{2} + 10 x + 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 23}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 23 = 22

x_{1, 2} = \frac{- 10 \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2 2}{2 \cdot 1}, x_{2} = \frac{- 10 - 2 2}{2 \cdot 1}

x = \frac{- 10 + 2 2}{2 \cdot 1} : - 5 + 2

x = \frac{- 10 - 2 2}{2 \cdot 1} : - 5 - 2

The solutions to the quadratic equation are:

x = - 5 + 2, x = - 5 - 2

∣ 2 a + 10 ∣ = ∣ 3 a - 8 ∣

(8 - i) - (- 82 + 2 i)

4 x^{2} - 8 x + 1 = 0

775

\frac{1}{3} \times \frac{1}{3}

What are the solutions to the equation x^2+10x+25=2 ?
The solutions to the equation x^2+10x+25=2 are x=-5+sqrt(2),x=-5-sqrt(2)
Find the zeros of x^2+10x+25=2
The zeros of x^2+10x+25=2 are x=-5+sqrt(2),x=-5-sqrt(2)