What is (2x^2-12x-14)/(4x^2+8x+4) ?

The solution to (2x^2-12x-14)/(4x^2+8x+4) is (x-7)/(2(x+1))

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simplify (2x^2-12x-14)/(4x^2+8x+4)

simplify

\frac{2 x ^{2} - 12 x - 14}{4 x ^{2} + 8 x + 4}

\frac{x - 7}{2 ( x + 1 )}

Solution steps

\frac{2 x ^{2} - 12 x - 14}{4 x ^{2} + 8 x + 4}

Factor

2 x^{2} - 12 x - 14 : 2 (x + 1) (x - 7)

= \frac{2 ( x + 1 ) ( x - 7 )}{4 x ^{2} + 8 x + 4}

Factor

4 x^{2} + 8 x + 4 : 4 (x + 1)^{2}

= \frac{2 ( x + 1 ) ( x - 7 )}{4 ( x + 1 ) ^{2}}

Factor the number:

4 = 2 \cdot 2

= \frac{2 ( x + 1 ) ( x - 7 )}{2 \cdot 2 ( x + 1 ) ^{2}}

Cancel the common factor:

2

= \frac{( x + 1 ) ( x - 7 )}{2 ( x + 1 ) ^{2}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(x + 1)^{2} = (x + 1) (x + 1)

= \frac{( x + 1 ) ( x - 7 )}{2 ( x + 1 ) ( x + 1 )}

Cancel the common factor:

x + 1

= \frac{x - 7}{2 ( x + 1 )}

3 x + 2%3 D^{5}

lo g_{5} (2 5^{300})

\frac{5}{5} - \frac{3}{5}

36 (43 - 12)

1372

What is (2x^2-12x-14)/(4x^2+8x+4) ?
The solution to (2x^2-12x-14)/(4x^2+8x+4) is (x-7)/(2(x+1))