What is (4-3i)+(9+2i) ?

The solution to (4-3i)+(9+2i) is 13-i

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simplify (4-3i)+(9+2i)

simplify

(4 - 3 i) + (9 + 2 i)

13 - i

Solution steps

(4 - 3 i) + (9 + 2 i)

Group the real part and the imaginary part of the complex number

(a + bi) + (c + d i) = (a + c) + (b + d) i

= (4 + 9) + (- 3 + 2) i

Simplify

(4 + 9) + (- 3 + 2) i : 13 - i

= 13 - i

\frac{x ^{2} + 12 x + 35}{x + 5}

\frac{3 x ^{2} - 15 x}{x ^{2} - 4 x - 5}

1 + i + i^{2}

(i \cdot 5)^{2} \cdot 3

(2 n + 2)^{2}