What is ((x^3-5x^2+7x-12))/((x-4)) ?

The solution to ((x^3-5x^2+7x-12))/((x-4)) is x^2-x+3

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simplify ((x^3-5x^2+7x-12))/((x-4))

simplify

\frac{( x ^{3} - 5 x ^{2} + 7 x - 12 )}{( x - 4 )}

x^{2} - x + 3

Solution steps

\frac{x ^{3} - 5 x ^{2} + 7 x - 12}{x - 4}

Factor

x^{3} - 5 x^{2} + 7 x - 12 : (x - 4) (x^{2} - x + 3)

= \frac{( x - 4 ) ( x ^{2} - x + 3 )}{x - 4}

Cancel the common factor:

x - 4

= x^{2} - x + 3

\frac{4 - i}{3 - i}

1.0 9^{2}

x^{3} - 5 x^{2} + 4

x^{3} - 5 x^{2} + 6

12 + 3 a + 3 a^{2} - 3 a + 3 b - 3 a^{2} - 3 b + 23 + 3 b^{2}

What is ((x^3-5x^2+7x-12))/((x-4)) ?
The solution to ((x^3-5x^2+7x-12))/((x-4)) is x^2-x+3