What are the solutions to the equation x^2+9x+81=0 ?

The solutions to the equation x^2+9x+81=0 are x=-9/2+i(9sqrt(3))/2 ,x=-9/2-i(9sqrt(3))/2

Find the zeros of x^2+9x+81=0

The zeros of x^2+9x+81=0 are x=-9/2+i(9sqrt(3))/2 ,x=-9/2-i(9sqrt(3))/2

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x^{2} + 9 x + 81 = 0

x = - \frac{9}{2} + i \frac{9 3}{2}, x = - \frac{9}{2} - i \frac{9 3}{2}

Solution steps

x^{2} + 9 x + 81 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 81}{2 \cdot 1}

Simplify

9^{2} - 4 \cdot 1 \cdot 81 : 93 i

x_{1, 2} = \frac{- 9 \pm 9 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 9 3 i}{2 \cdot 1}, x_{2} = \frac{- 9 - 9 3 i}{2 \cdot 1}

x = \frac{- 9 + 9 3 i}{2 \cdot 1} : - \frac{9}{2} + i \frac{9 3}{2}

x = \frac{- 9 - 9 3 i}{2 \cdot 1} : - \frac{9}{2} - i \frac{9 3}{2}

The solutions to the quadratic equation are:

x = - \frac{9}{2} + i \frac{9 3}{2}, x = - \frac{9}{2} - i \frac{9 3}{2}

p = (0.0821) (0.039)

0.1 4^{2}

\frac{7 x}{4} - 1 - \frac{x}{8} = x + \frac{5 x}{8} + 1

3 u + 3 (u + 1) > 2 u + 7

4 y - 2 (6 - y) = 6

What are the solutions to the equation x^2+9x+81=0 ?
The solutions to the equation x^2+9x+81=0 are x=-9/2+i(9sqrt(3))/2 ,x=-9/2-i(9sqrt(3))/2
Find the zeros of x^2+9x+81=0
The zeros of x^2+9x+81=0 are x=-9/2+i(9sqrt(3))/2 ,x=-9/2-i(9sqrt(3))/2