What is (x^2-9)/(x^2+x-12) ?

The solution to (x^2-9)/(x^2+x-12) is (x+3)/(x+4)

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simplify (x^2-9)/(x^2+x-12)

simplify

\frac{x ^{2} - 9}{x ^{2} + x - 12}

\frac{x + 3}{x + 4}

Solution steps

\frac{x ^{2} - 9}{x ^{2} + x - 12}

Factor

x^{2} - 9 : (x + 3) (x - 3)

= \frac{( x + 3 ) ( x - 3 )}{x ^{2} + x - 12}

Factor

x^{2} + x - 12 : (x - 3) (x + 4)

= \frac{( x + 3 ) ( x - 3 )}{( x - 3 ) ( x + 4 )}

Cancel the common factor:

x - 3

= \frac{x + 3}{x + 4}

\frac{3.9 - 2}{3.9 - 4}

(4 - 3 x)^{3}

13 \times 18 \times 26

\frac{30}{4}