What are the solutions to the equation x^2+10x=21 ?

The solutions to the equation x^2+10x=21 are x=-5+sqrt(46),x=-5-sqrt(46)

Find the zeros of x^2+10x=21

The zeros of x^2+10x=21 are x=-5+sqrt(46),x=-5-sqrt(46)

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x^{2} + 10 x = 21

x = - 5 + 46, x = - 5 - 46

Solution steps

x^{2} + 10 x = 21

Move

21

to the left side

x^{2} + 10 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 21 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 21) = 246

x_{1, 2} = \frac{- 10 \pm 2 46}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 2 46}{2 \cdot 1}, x_{2} = \frac{- 10 - 2 46}{2 \cdot 1}

x = \frac{- 10 + 2 46}{2 \cdot 1} : - 5 + 46

x = \frac{- 10 - 2 46}{2 \cdot 1} : - 5 - 46

The solutions to the quadratic equation are:

x = - 5 + 46, x = - 5 - 46

x^{2} - 7 x + 25 = 0

ln (3 x) \leq 5

y^{4} - 3 y^{2} - 28

- 699 [- 2 (132 + 84) - 4 (- 52 + (- 108))] + 499

\frac{3 + 9 i}{1 + i}

What are the solutions to the equation x^2+10x=21 ?
The solutions to the equation x^2+10x=21 are x=-5+sqrt(46),x=-5-sqrt(46)
Find the zeros of x^2+10x=21
The zeros of x^2+10x=21 are x=-5+sqrt(46),x=-5-sqrt(46)