What is factor 3x^4+8x^3+6x^2+3x-2 ?

The solution to factor 3x^4+8x^3+6x^2+3x-2 is (3x-1)(x+2)(x^2+x+1)

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factor 3x^4+8x^3+6x^2+3x-2

factor

3 x^{4} + 8 x^{3} + 6 x^{2} + 3 x - 2

(3 x - 1) (x + 2) (x^{2} + x + 1)

Solution steps

3 x^{4} + 8 x^{3} + 6 x^{2} + 3 x - 2

Use the rational root theorem

= (3 x - 1) \frac{3 x ^{4} + 8 x ^{3} + 6 x ^{2} + 3 x - 2}{3 x - 1}

\frac{3 x ^{4} + 8 x ^{3} + 6 x ^{2} + 3 x - 2}{3 x - 1} = x^{3} + 3 x^{2} + 3 x + 2

= (3 x - 1) (x^{3} + 3 x^{2} + 3 x + 2)

Factor

x^{3} + 3 x^{2} + 3 x + 2 : (x + 2) (x^{2} + x + 1)

= (3 x - 1) (x + 2) (x^{2} + x + 1)

\frac{- 21}{- 3}

x^{4} \cdot 2 x

216 v

3 x^{2} - 23 x + 14

3 s^{4} + 6 s^{3} + 27 s^{2}

What is factor 3x^4+8x^3+6x^2+3x-2 ?
The solution to factor 3x^4+8x^3+6x^2+3x-2 is (3x-1)(x+2)(x^2+x+1)