What are the solutions to the equation (2x+3)^2=25 ?

The solutions to the equation (2x+3)^2=25 are x=1,x=-4

Find the zeros of (2x+3)^2=25

The zeros of (2x+3)^2=25 are x=1,x=-4

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(2 x + 3)^{2} = 25

x = 1, x = - 4

Solution steps

(2 x + 3)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 3 = 25 : x = 1

Solve

2 x + 3 = - 25 : x = - 4

The solutions to the quadratic equation are:

x = 1, x = - 4

- 4 x - 19 > 33

4 d^{2} + 15 d - 4 = 0

4 r^{2} - 7 = 29

\frac{5 7}{35}

2 x + 5 \geq - 7

What are the solutions to the equation (2x+3)^2=25 ?
The solutions to the equation (2x+3)^2=25 are x=1,x=-4
Find the zeros of (2x+3)^2=25
The zeros of (2x+3)^2=25 are x=1,x=-4