What are the solutions to the equation 4r^2-7=29 ?

The solutions to the equation 4r^2-7=29 are r=3,r=-3

Find the zeros of 4r^2-7=29

The zeros of 4r^2-7=29 are r=3,r=-3

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4 r^{2} - 7 = 29

r = 3, r = - 3

Solution steps

4 r^{2} - 7 = 29

Move

7

to the right side

4 r^{2} = 36

Divide both sides by

4

r^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = 9, r = - 9

9 = 3

- 9 = - 3

r = 3, r = - 3

\frac{5 7}{35}

2 x + 5 \geq - 7

2 a^{- \frac{1}{2}}

C = \frac{25 ( 0.6 )}{100 - 0.6}

2 = \frac{3 x + 22}{5}

What are the solutions to the equation 4r^2-7=29 ?
The solutions to the equation 4r^2-7=29 are r=3,r=-3
Find the zeros of 4r^2-7=29
The zeros of 4r^2-7=29 are r=3,r=-3