What is ((2hk^3)^3)/((-h^2k^2)^2) ?

The solution to ((2hk^3)^3)/((-h^2k^2)^2) is (8k^5)/h

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simplify ((2hk^3)^3)/((-h^2k^2)^2)

simplify

\frac{( 2 h k ^{3} ) ^{3}}{( - h ^{2} k ^{2} ) ^{2}}

\frac{8 k ^{5}}{h}

Solution steps

\frac{( 2 h k ^{3} ) ^{3}}{( - h ^{2} k ^{2} ) ^{2}}

Simplify

(2 h k^{3})^{3} : 8 h^{3} k^{9}

= \frac{8 h ^{3} k ^{9}}{( - h ^{2} k ^{2} ) ^{2}}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- h^{2} k^{2})^{2} = (h^{2} k^{2})^{2}

= \frac{8 h ^{3} k ^{9}}{( h ^{2} k ^{2} ) ^{2}}

Simplify

(h^{2} k^{2})^{2} : h^{4} k^{4}

= \frac{8 h ^{3} k ^{9}}{h ^{4} k ^{4}}

Simplify

\frac{h ^{3}}{h ^{4}} : \frac{1}{h}

= \frac{8 k ^{9}}{h k ^{4}}

Simplify

\frac{k ^{9}}{k ^{4}} : k^{5}

= \frac{8 k ^{5}}{h}

(x + y)^{2} + 3 (x + y) + 2

2 x^{2} + 3 x = 4 x + 12

2 x^{3} + x y^{2} - 2 x^{2} y - y^{3}

\frac{3}{10} x - \frac{1}{5} = - 2

p + 9 < 7

What is ((2hk^3)^3)/((-h^2k^2)^2) ?
The solution to ((2hk^3)^3)/((-h^2k^2)^2) is (8k^5)/h