What are the solutions to the equation -2x^2+x+3=0 ?

The solutions to the equation -2x^2+x+3=0 are x=-1,x= 3/2

Find the zeros of -2x^2+x+3=0

The zeros of -2x^2+x+3=0 are x=-1,x= 3/2

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- 2 x^{2} + x + 3 = 0

x = - 1, x = \frac{3}{2}

Solution steps

- 2 x^{2} + x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 2 ) \cdot 3}{2 ( - 2 )}

1^{2} - 4 (- 2) \cdot 3 = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 ( - 2 )}, x_{2} = \frac{- 1 - 5}{2 ( - 2 )}

x = \frac{- 1 + 5}{2 ( - 2 )} : - 1

x = \frac{- 1 - 5}{2 ( - 2 )} : \frac{3}{2}

The solutions to the quadratic equation are:

x = - 1, x = \frac{3}{2}

5 x - 6 = 4 x + 8

2 x + 3 \geq 19

\frac{2}{5 ^{\frac{3}{2}}}

\frac{1}{2 ^{6}}

15 + 8

What are the solutions to the equation -2x^2+x+3=0 ?
The solutions to the equation -2x^2+x+3=0 are x=-1,x= 3/2
Find the zeros of -2x^2+x+3=0
The zeros of -2x^2+x+3=0 are x=-1,x= 3/2