What is (m^2-n^2m)22m^2n^2 ?

The solution to (m^2-n^2m)22m^2n^2 is 22m^2n^2(m^2-mn^2)

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simplify (m^2-n^2m)22m^2n^2

simplify

(m^{2} - n^{2} m) 22 m^{2} n^{2}

22 m^{2} n^{2} (m^{2} - m n^{2})

Solution steps

(m^{2} - n^{2} m) \cdot 22 m^{2} n^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

m^{2} n^{2} = (mn)^{2}

= 22 (m^{2} - m n^{2}) (mn)^{2}

(mn)^{2} = m^{2} n^{2}

= 22 m^{2} n^{2} (m^{2} - m n^{2})

e^{- 0.544}

(2 x^{4}) (4 x^{5})

e^{- 14 l n (x)}

e^{- 2} e^{x}

e^{- \frac{8}{32}}

What is (m^2-n^2m)22m^2n^2 ?
The solution to (m^2-n^2m)22m^2n^2 is 22m^2n^2(m^2-mn^2)