What is e^{-(aln(cx+d))/(bc)} ?

The solution to e^{-(aln(cx+d))/(bc)} is 1/((cx+d)^{\frac{a){cb}}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify e^{-(aln(cx+d))/(bc)}

simplify

e^{- \frac{a l n ( c x + d )}{b c}}

\frac{1}{( c x + d ) ^{\frac{a}{c b}}}

Solution steps

e^{- \frac{a l n ( c x + d )}{b c}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{\frac{a l n ( c x + d )}{b c}}}

e^{\frac{a l n ( c x + d )}{b c}} = (c x + d)^{\frac{a}{c b}}

= \frac{1}{( c x + d ) ^{\frac{a}{b c}}}

5 a^{3} b c^{2} (4 ab c^{5})

e^{- 2 x} \times 2 e^{2 x}

y^{2} (x^{5} y^{3})

- 2000 \cdot e^{- \frac{π}{2}}

x^{3} \times y^{3}

What is e^{-(aln(cx+d))/(bc)} ?
The solution to e^{-(aln(cx+d))/(bc)} is 1/((cx+d)^{\frac{a){cb}}}