What is (x+1)^2\times (x-1)^2 ?

The solution to (x+1)^2\times (x-1)^2 is (x+1)^2(x-1)^2

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simplify (x+1)^2\times (x-1)^2

simplify

(x + 1)^{2} \cdot (x - 1)^{2}

(x + 1)^{2} (x - 1)^{2}

Solution steps

(x + 1)^{2} (x - 1)^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(x + 1)^{2} (x - 1)^{2} = ((x + 1) (x - 1))^{2}

= ((x + 1) (x - 1))^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= (x + 1)^{2} (x - 1)^{2}

6.7 \times 10 e^{- 11}

e^{(- l n ∣ x ∣)}

x \cdot x

\frac{e ^{k x}}{e ^{- k x}}

What is (x+1)^2\times (x-1)^2 ?
The solution to (x+1)^2\times (x-1)^2 is (x+1)^2(x-1)^2