What are the solutions to the equation 2x^2-11x=40 ?

The solutions to the equation 2x^2-11x=40 are x=8,x=-5/2

Find the zeros of 2x^2-11x=40

The zeros of 2x^2-11x=40 are x=8,x=-5/2

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2 x^{2} - 11 x = 40

x = 8, x = - \frac{5}{2}

Decimal Notation

x = 8, x = - 2.5

Solution steps

2 x^{2} - 11 x = 40

Move

40

to the left side

2 x^{2} - 11 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 2 ( - 40 )}{2 \cdot 2}

(- 11)^{2} - 4 \cdot 2 (- 40) = 21

x_{1, 2} = \frac{- ( - 11 ) \pm 21}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 21}{2 \cdot 2}, x_{2} = \frac{- ( - 11 ) - 21}{2 \cdot 2}

x = \frac{- ( - 11 ) + 21}{2 \cdot 2} : 8

x = \frac{- ( - 11 ) - 21}{2 \cdot 2} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = 8, x = - \frac{5}{2}

8 x^{2} + 6 x - 5

\frac{x + 5}{2} = 10

\frac{m ^{2} - 25}{5 + m}

a^{4} + 4

What are the solutions to the equation 2x^2-11x=40 ?
The solutions to the equation 2x^2-11x=40 are x=8,x=-5/2
Find the zeros of 2x^2-11x=40
The zeros of 2x^2-11x=40 are x=8,x=-5/2