What are the solutions to the equation b^2=4 ?

The solutions to the equation b^2=4 are b=2,b=-2

Find the zeros of b^2=4

The zeros of b^2=4 are b=2,b=-2

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b^{2} = 4

b = 2, b = - 2

Solution steps

b^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 4, b = - 4

4 = 2

- 4 = - 2

b = 2, b = - 2

75 g^{3} h^{2} - 125 g h

(27 t^{3})^{\frac{2}{3}}

x + 1.6 = 0.8

\frac{10 x y}{5 y}

4 x - 5 \leq - 25

What are the solutions to the equation b^2=4 ?
The solutions to the equation b^2=4 are b=2,b=-2
Find the zeros of b^2=4
The zeros of b^2=4 are b=2,b=-2