What is (8e^6f^{-4})^{-1} ?

The solution to (8e^6f^{-4})^{-1} is (f^4)/(8e^6)

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simplify (8e^6f^{-4})^{-1}

simplify

(8 e^{6} f^{- 4})^{- 1}

\frac{f ^{4}}{8 e ^{6}}

Solution steps

(8 e^{6} f^{- 4})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{1}{8 e ^{6} f ^{- 4}}

Multiply

8 e^{6} f^{- 4} : \frac{8 e ^{6}}{f ^{4}}

= \frac{1}{\frac{8 e ^{6}}{f ^{4}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{f ^{4}}{8 e ^{6}}

x + 4 \cdot x - 5

1 + x^{2} \times 1 - x^{2}

((2^{5})^{2})^{4}

e^{- 3} (- \frac{2}{2} - 1)