What are the solutions to the equation 5x^2-3x-1=0 ?

The solutions to the equation 5x^2-3x-1=0 are x=(3+sqrt(29))/(10),x=(3-sqrt(29))/(10)

Find the zeros of 5x^2-3x-1=0

The zeros of 5x^2-3x-1=0 are x=(3+sqrt(29))/(10),x=(3-sqrt(29))/(10)

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5 x^{2} - 3 x - 1 = 0

x = \frac{3 + 29}{10}, x = \frac{3 - 29}{10}

Solution steps

5 x^{2} - 3 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 5 ( - 1 )}{2 \cdot 5}

(- 3)^{2} - 4 \cdot 5 (- 1) = 29

x_{1, 2} = \frac{- ( - 3 ) \pm 29}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 29}{2 \cdot 5}, x_{2} = \frac{- ( - 3 ) - 29}{2 \cdot 5}

x = \frac{- ( - 3 ) + 29}{2 \cdot 5} : \frac{3 + 29}{10}

x = \frac{- ( - 3 ) - 29}{2 \cdot 5} : \frac{3 - 29}{10}

The solutions to the quadratic equation are:

x = \frac{3 + 29}{10}, x = \frac{3 - 29}{10}

y^{2} = - 4

\frac{j}{4} = 3

4 p - 1 \leq 3 p - 10

- 2 y = - 10

a^{3} + 64 b^{3}

What are the solutions to the equation 5x^2-3x-1=0 ?
The solutions to the equation 5x^2-3x-1=0 are x=(3+sqrt(29))/(10),x=(3-sqrt(29))/(10)
Find the zeros of 5x^2-3x-1=0
The zeros of 5x^2-3x-1=0 are x=(3+sqrt(29))/(10),x=(3-sqrt(29))/(10)