What are the solutions to the equation solvefor x,y^2=4p(x)x ?

The solutions to the equation solvefor x,y^2=4p(x)x are x= y/(2sqrt(p)),x=-y/(2sqrt(p));\quad p\ne 0

Find the zeros of solvefor x,y^2=4p(x)x

The zeros of solvefor x,y^2=4p(x)x are x= y/(2sqrt(p)),x=-y/(2sqrt(p));\quad p\ne 0

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solve for

x, y^{2} = 4 p (x) x

x = \frac{y}{2 p}, x = - \frac{y}{2 p}; p \neq = 0

Solution steps

y^{2} = 4 p (x) x

Switch sides

4 p xx = y^{2}

Simplify

4 p x^{2} = y^{2}

Divide both sides by

4 p; p \neq = 0

\frac{4 p x ^{2}}{4 p} = \frac{y ^{2}}{4 p}; p \neq = 0

x^{2} = \frac{y ^{2}}{4 p}; p \neq = 0

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{y ^{2}}{4 p}, x = - \frac{y ^{2}}{4 p}; p \neq = 0

Simplify

\frac{y ^{2}}{4 p} : \frac{y}{2 p}

Simplify

- \frac{y ^{2}}{4 p} : - \frac{y}{2 p}

x = \frac{y}{2 p}, x = - \frac{y}{2 p}; p \neq = 0

y, x + y = 12

r, v = π r^{2} h

7 c - 2 x = 8 c - x

y, 2 x - 4 y = 4

y, 4 x + y = 8

What are the solutions to the equation solvefor x,y^2=4p(x)x ?
The solutions to the equation solvefor x,y^2=4p(x)x are x= y/(2sqrt(p)),x=-y/(2sqrt(p));\quad p\ne 0
Find the zeros of solvefor x,y^2=4p(x)x
The zeros of solvefor x,y^2=4p(x)x are x= y/(2sqrt(p)),x=-y/(2sqrt(p));\quad p\ne 0