What are the solutions to the equation x^2-0.1x+1=0 ?

The solutions to the equation x^2-0.1x+1=0 are x= 1/20+i(sqrt(399))/(20),x= 1/20-i(sqrt(399))/(20)

Find the zeros of x^2-0.1x+1=0

The zeros of x^2-0.1x+1=0 are x= 1/20+i(sqrt(399))/(20),x= 1/20-i(sqrt(399))/(20)

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x^{2} - 0.1 x + 1 = 0

x = \frac{1}{20} + i \frac{399}{20}, x = \frac{1}{20} - i \frac{399}{20}

Solution steps

x^{2} - 0.1 x + 1 = 0

Multiply both sides by

10

10 x^{2} - x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 10 \cdot 10}{2 \cdot 10}

Simplify

(- 1)^{2} - 4 \cdot 10 \cdot 10 : 399 i

x_{1, 2} = \frac{- ( - 1 ) \pm 399 i}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 399 i}{2 \cdot 10}, x_{2} = \frac{- ( - 1 ) - 399 i}{2 \cdot 10}

x = \frac{- ( - 1 ) + 399 i}{2 \cdot 10} : \frac{1}{20} + i \frac{399}{20}

x = \frac{- ( - 1 ) - 399 i}{2 \cdot 10} : \frac{1}{20} - i \frac{399}{20}

The solutions to the quadratic equation are:

x = \frac{1}{20} + i \frac{399}{20}, x = \frac{1}{20} - i \frac{399}{20}

6 v - 19 = 3 v - 4

\frac{5 ^{- 4}}{5 ^{3}}

2 0^{5}

x^{4} - y^{4} - (x - y) (x + y)

\frac{3}{9} = \frac{v}{6}

What are the solutions to the equation x^2-0.1x+1=0 ?
The solutions to the equation x^2-0.1x+1=0 are x= 1/20+i(sqrt(399))/(20),x= 1/20-i(sqrt(399))/(20)
Find the zeros of x^2-0.1x+1=0
The zeros of x^2-0.1x+1=0 are x= 1/20+i(sqrt(399))/(20),x= 1/20-i(sqrt(399))/(20)