What are the solutions to the equation 0=3x^2-27x+54 ?

The solutions to the equation 0=3x^2-27x+54 are x=6,x=3

Find the zeros of 0=3x^2-27x+54

The zeros of 0=3x^2-27x+54 are x=6,x=3

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0 = 3 x^{2} - 27 x + 54

x = 6, x = 3

Solution steps

0 = 3 x^{2} - 27 x + 54

Switch sides

3 x^{2} - 27 x + 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 \cdot 3 \cdot 54}{2 \cdot 3}

(- 27)^{2} - 4 \cdot 3 \cdot 54 = 9

x_{1, 2} = \frac{- ( - 27 ) \pm 9}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 27 ) + 9}{2 \cdot 3}, x_{2} = \frac{- ( - 27 ) - 9}{2 \cdot 3}

x = \frac{- ( - 27 ) + 9}{2 \cdot 3} : 6

x = \frac{- ( - 27 ) - 9}{2 \cdot 3} : 3

The solutions to the quadratic equation are:

x = 6, x = 3

- 5 x > - 30

- 3 x^{2} + 2 x - 3 = 0

45 \cdot 8

9 a b^{2} - 12 b

4 ∣ x ∣ - 2 \geq 10

What are the solutions to the equation 0=3x^2-27x+54 ?
The solutions to the equation 0=3x^2-27x+54 are x=6,x=3
Find the zeros of 0=3x^2-27x+54
The zeros of 0=3x^2-27x+54 are x=6,x=3