What are the solutions to the equation -3x^2+2x-3=0 ?

The solutions to the equation -3x^2+2x-3=0 are x= 1/3-i(2sqrt(2))/3 ,x= 1/3+i(2sqrt(2))/3

Find the zeros of -3x^2+2x-3=0

The zeros of -3x^2+2x-3=0 are x= 1/3-i(2sqrt(2))/3 ,x= 1/3+i(2sqrt(2))/3

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- 3 x^{2} + 2 x - 3 = 0

x = \frac{1}{3} - i \frac{2 2}{3}, x = \frac{1}{3} + i \frac{2 2}{3}

Solution steps

- 3 x^{2} + 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 3 ) ( - 3 )}{2 ( - 3 )}

Simplify

2^{2} - 4 (- 3) (- 3) : 42 i

x_{1, 2} = \frac{- 2 \pm 4 2 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 2 + 4 2 i}{2 ( - 3 )}, x_{2} = \frac{- 2 - 4 2 i}{2 ( - 3 )}

x = \frac{- 2 + 4 2 i}{2 ( - 3 )} : \frac{1}{3} - i \frac{2 2}{3}

x = \frac{- 2 - 4 2 i}{2 ( - 3 )} : \frac{1}{3} + i \frac{2 2}{3}

The solutions to the quadratic equation are:

x = \frac{1}{3} - i \frac{2 2}{3}, x = \frac{1}{3} + i \frac{2 2}{3}

45 \cdot 8

9 a b^{2} - 12 b

4 ∣ x ∣ - 2 \geq 10

8 a^{2} - 18 a + 7

\frac{3 - 1}{1 + 9}

What are the solutions to the equation -3x^2+2x-3=0 ?
The solutions to the equation -3x^2+2x-3=0 are x= 1/3-i(2sqrt(2))/3 ,x= 1/3+i(2sqrt(2))/3
Find the zeros of -3x^2+2x-3=0
The zeros of -3x^2+2x-3=0 are x= 1/3-i(2sqrt(2))/3 ,x= 1/3+i(2sqrt(2))/3