What are the solutions to the equation x^2+12x+33=0 ?

The solutions to the equation x^2+12x+33=0 are x=-6+sqrt(3),x=-6-sqrt(3)

Find the zeros of x^2+12x+33=0

The zeros of x^2+12x+33=0 are x=-6+sqrt(3),x=-6-sqrt(3)

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x^{2} + 12 x + 33 = 0

x = - 6 + 3, x = - 6 - 3

Solution steps

x^{2} + 12 x + 33 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 33}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 33 = 23

x_{1, 2} = \frac{- 12 \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2 3}{2 \cdot 1}, x_{2} = \frac{- 12 - 2 3}{2 \cdot 1}

x = \frac{- 12 + 2 3}{2 \cdot 1} : - 6 + 3

x = \frac{- 12 - 2 3}{2 \cdot 1} : - 6 - 3

The solutions to the quadratic equation are:

x = - 6 + 3, x = - 6 - 3

x > - 1 and x \leq 2

32 x^{4} y^{9}

∣ y ∣ = 6

- 5 p^{3} + 6 p^{2} + 45 p - 54

- 2 + 4

What are the solutions to the equation x^2+12x+33=0 ?
The solutions to the equation x^2+12x+33=0 are x=-6+sqrt(3),x=-6-sqrt(3)
Find the zeros of x^2+12x+33=0
The zeros of x^2+12x+33=0 are x=-6+sqrt(3),x=-6-sqrt(3)