What are the solutions to the equation x^2-4x+85=0 ?

The solutions to the equation x^2-4x+85=0 are x=2+9i,x=2-9i

Find the zeros of x^2-4x+85=0

The zeros of x^2-4x+85=0 are x=2+9i,x=2-9i

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x^{2} - 4 x + 85 = 0

x = 2 + 9 i, x = 2 - 9 i

Solution steps

x^{2} - 4 x + 85 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 85}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 85 : 18 i

x_{1, 2} = \frac{- ( - 4 ) \pm 18 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 18 i}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 18 i}{2 \cdot 1}

x = \frac{- ( - 4 ) + 18 i}{2 \cdot 1} : 2 + 9 i

x = \frac{- ( - 4 ) - 18 i}{2 \cdot 1} : 2 - 9 i

The solutions to the quadratic equation are:

x = 2 + 9 i, x = 2 - 9 i

z^{2} - x^{2}

3 x + \frac{23}{32} = \frac{7}{8} - \frac{1}{16} x - \frac{1}{4}

x^{5} - x^{4} y^{3}

1 + \frac{x + 1}{3} = x - \frac{3 x + 1}{8}

2^{4} \cdot 3

What are the solutions to the equation x^2-4x+85=0 ?
The solutions to the equation x^2-4x+85=0 are x=2+9i,x=2-9i
Find the zeros of x^2-4x+85=0
The zeros of x^2-4x+85=0 are x=2+9i,x=2-9i