What are the solutions to the equation 3x^2-18x+5=47 ?

The solutions to the equation 3x^2-18x+5=47 are x=3+sqrt(23),x=3-sqrt(23)

Find the zeros of 3x^2-18x+5=47

The zeros of 3x^2-18x+5=47 are x=3+sqrt(23),x=3-sqrt(23)

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3 x^{2} - 18 x + 5 = 47

x = 3 + 23, x = 3 - 23

Solution steps

3 x^{2} - 18 x + 5 = 47

Move

47

to the left side

3 x^{2} - 18 x - 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 3 ( - 42 )}{2 \cdot 3}

(- 18)^{2} - 4 \cdot 3 (- 42) = 623

x_{1, 2} = \frac{- ( - 18 ) \pm 6 23}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 6 23}{2 \cdot 3}, x_{2} = \frac{- ( - 18 ) - 6 23}{2 \cdot 3}

x = \frac{- ( - 18 ) + 6 23}{2 \cdot 3} : 3 + 23

x = \frac{- ( - 18 ) - 6 23}{2 \cdot 3} : 3 - 23

The solutions to the quadratic equation are:

x = 3 + 23, x = 3 - 23

0 = - 3 x^{2} + 6 x

4 x - 12 \leq 16 + 8 x

∣ 4 x - 9 ∣ - 6 = 2

\frac{3}{5 - 2}

2 x^{2} + 128 = 0

What are the solutions to the equation 3x^2-18x+5=47 ?
The solutions to the equation 3x^2-18x+5=47 are x=3+sqrt(23),x=3-sqrt(23)
Find the zeros of 3x^2-18x+5=47
The zeros of 3x^2-18x+5=47 are x=3+sqrt(23),x=3-sqrt(23)