What is the answer to solvefor x,xy+yz+xz=1 ?

The answer to solvefor x,xy+yz+xz=1 is x=(1-yz)/(y+z);\quad y\ne-z

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solvefor x,xy+yz+xz=1

solve for

x, x y + yz + x z = 1

x = \frac{1 - yz}{y + z}; y \neq = - z

Solution steps

x y + yz + x z = 1

Move

yz

to the right side

x y + x z = 1 - yz

Factor

x y + x z : x (y + z)

x (y + z) = 1 - yz

Divide both sides by

y + z; y \neq = - z

x = \frac{1 - yz}{y + z}; y \neq = - z

x - \frac{x}{12} = \frac{11}{3}

3 (4 z - 4) = 12

y, - 4 x - 6 y = 2

y, 6 x + 3 y = 24

y, 2 x + 8 y = 32

What is the answer to solvefor x,xy+yz+xz=1 ?
The answer to solvefor x,xy+yz+xz=1 is x=(1-yz)/(y+z);\quad y\ne-z