What is the answer to (x+10)^2=(5-x)^2 ?

The answer to (x+10)^2=(5-x)^2 is x=-5/2

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(x+10)^2=(5-x)^2

(x + 10)^{2} = (5 - x)^{2}

x = - \frac{5}{2}

Decimal Notation

x = - 2.5

Solution steps

(x + 10)^{2} = (5 - x)^{2}

Expand

(x + 10)^{2} : x^{2} + 20 x + 100

Expand

(5 - x)^{2} : 25 - 10 x + x^{2}

x^{2} + 20 x + 100 = 25 - 10 x + x^{2}

Move

100

to the right side

x^{2} + 20 x = x^{2} - 10 x - 75

Subtract

x^{2} - 10 x

from both sides

x^{2} + 20 x - (x^{2} - 10 x) = x^{2} - 10 x - 75 - (x^{2} - 10 x)

Simplify

30 x = - 75

Divide both sides by

30

x = - \frac{5}{2}

y, 5 x - 4 y = 20

y, 3 x - 4 y = - 12

y, x + y - 3 = 0

y, 4 x + y = 0

1 - 10 x = - 5 x + 10

What is the answer to (x+10)^2=(5-x)^2 ?
The answer to (x+10)^2=(5-x)^2 is x=-5/2
Solve for x: (x+10)^2=(5-x)^2
The solution is x=-5/2