What is ((7^{-1})/(2^{-1)+3^{-1}+6^{-1}})^{-2} ?

The solution to ((7^{-1})/(2^{-1)+3^{-1}+6^{-1}})^{-2} is 49

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simplify ((7^{-1})/(2^{-1)+3^{-1}+6^{-1}})^{-2}

simplify

(\frac{7 ^{- 1}}{2 ^{- 1} + 3 ^{- 1} + 6 ^{- 1}})^{- 2}

49

Solution steps

(\frac{7 ^{- 1}}{2 ^{- 1} + 3 ^{- 1} + 6 ^{- 1}})^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{7 ^{- 1}}{2 ^{- 1} + 3 ^{- 1} + 6 ^{- 1}})^{- 2} = \frac{1}{( \frac{7 ^{- 1}}{2 ^{- 1} + 3 ^{- 1} + 6 ^{- 1}} ) ^{2}}

= \frac{1}{( \frac{7 ^{- 1}}{2 ^{- 1} + 3 ^{- 1} + 6 ^{- 1}} ) ^{2}}

(\frac{7 ^{- 1}}{2 ^{- 1} + 3 ^{- 1} + 6 ^{- 1}})^{2} = \frac{1}{49}

= \frac{1}{\frac{1}{49}}

\frac{1}{\frac{1}{49}} = 49

= 49

96 - 48 m n^{2} + 144 n^{3}

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4 x^{2} - 13 x y + 10 y^{2}

What is ((7^{-1})/(2^{-1)+3^{-1}+6^{-1}})^{-2} ?
The solution to ((7^{-1})/(2^{-1)+3^{-1}+6^{-1}})^{-2} is 49