What is (2-b)(1+2b)+(1+b)(b^3-3b) ?

The solution to (2-b)(1+2b)+(1+b)(b^3-3b) is b^4+b^3-5b^2+2

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simplify (2-b)(1+2b)+(1+b)(b^3-3b)

simplify

(2 - b) (1 + 2 b) + (1 + b) (b^{3} - 3 b)

b^{4} + b^{3} - 5 b^{2} + 2

Solution steps

(2 - b) (1 + 2 b) + (1 + b) (b^{3} - 3 b)

Expand

(2 - b) (1 + 2 b) : 2 + 3 b - 2 b^{2}

= 2 + 3 b - 2 b^{2} + (1 + b) (b^{3} - 3 b)

Expand

(1 + b) (b^{3} - 3 b) : b^{3} - 3 b + b^{4} - 3 b^{2}

= 2 + 3 b - 2 b^{2} + b^{3} - 3 b + b^{4} - 3 b^{2}

Group like terms

= b^{4} + b^{3} - 2 b^{2} - 3 b^{2} + 3 b - 3 b + 2

Add similar elements:

- 2 b^{2} - 3 b^{2} = - 5 b^{2}

= b^{4} + b^{3} - 5 b^{2} + 3 b - 3 b + 2

Add similar elements:

3 b - 3 b = 0

= b^{4} + b^{3} - 5 b^{2} + 2

- 13 x + 1 \leq - 25

(\frac{1}{4} a^{8} b^{4})^{2}

\frac{s}{4} - 1 = 3

0.1 + 2 (0.4 x + 1) = 12

\frac{x ^{2} ( x + 2 )}{( x + 2 ) ( x + 1 )} \leq 0

What is (2-b)(1+2b)+(1+b)(b^3-3b) ?
The solution to (2-b)(1+2b)+(1+b)(b^3-3b) is b^4+b^3-5b^2+2