What are the solutions to the equation 3x^2-122x+1195=0 ?

The solutions to the equation 3x^2-122x+1195=0 are x=(61+2sqrt(34))/3 ,x=(61-2sqrt(34))/3

Find the zeros of 3x^2-122x+1195=0

The zeros of 3x^2-122x+1195=0 are x=(61+2sqrt(34))/3 ,x=(61-2sqrt(34))/3

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3 x^{2} - 122 x + 1195 = 0

x = \frac{61 + 2 34}{3}, x = \frac{61 - 2 34}{3}

Solution steps

3 x^{2} - 122 x + 1195 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 122 ) \pm ( - 122 ) ^{2} - 4 \cdot 3 \cdot 1195}{2 \cdot 3}

(- 122)^{2} - 4 \cdot 3 \cdot 1195 = 434

x_{1, 2} = \frac{- ( - 122 ) \pm 4 34}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 122 ) + 4 34}{2 \cdot 3}, x_{2} = \frac{- ( - 122 ) - 4 34}{2 \cdot 3}

x = \frac{- ( - 122 ) + 4 34}{2 \cdot 3} : \frac{61 + 2 34}{3}

x = \frac{- ( - 122 ) - 4 34}{2 \cdot 3} : \frac{61 - 2 34}{3}

The solutions to the quadratic equation are:

x = \frac{61 + 2 34}{3}, x = \frac{61 - 2 34}{3}

17 + 0.03 x \geq 9 + 0.07 x

\frac{2 x - 1}{9} = 3

- 3 x + 2 \leq - 7

3 (x - 2)^{2} (4 x + 1)^{4} + (x - 2)^{3} (4 x + 1)^{3}

\frac{8}{2} - \frac{7}{12}

What are the solutions to the equation 3x^2-122x+1195=0 ?
The solutions to the equation 3x^2-122x+1195=0 are x=(61+2sqrt(34))/3 ,x=(61-2sqrt(34))/3
Find the zeros of 3x^2-122x+1195=0
The zeros of 3x^2-122x+1195=0 are x=(61+2sqrt(34))/3 ,x=(61-2sqrt(34))/3