What is the answer to solvefor x,xy= 1/(z^2)+xz ?

The answer to solvefor x,xy= 1/(z^2)+xz is x= 1/(z^2(y-z));\quad y\ne z

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solvefor x,xy= 1/(z^2)+xz

solve for

x, x y = \frac{1}{z ^{2}} + x z

x = \frac{1}{z ^{2} ( y - z )}; y \neq = z

Solution steps

x y = \frac{1}{z ^{2}} + x z

Move

x z

to the left side

x y - x z = \frac{1}{z ^{2}}

Factor

x y - x z : x (y - z)

x (y - z) = \frac{1}{z ^{2}}

Divide both sides by

y - z; y \neq = z

x = \frac{1}{z ^{2} ( y - z )}; y \neq = z

\frac{3}{4} x - 7 = \frac{1}{2} x

2 x + 7 = 23 - 3 x

5 x = 7 (x - 2) + 2

y, x - 6 y = 10

y, 6 x + 7 y = 4 x + 4 y

What is the answer to solvefor x,xy= 1/(z^2)+xz ?
The answer to solvefor x,xy= 1/(z^2)+xz is x= 1/(z^2(y-z));\quad y\ne z