What is the answer to (x-7)^2=(x+4)^2 ?

The answer to (x-7)^2=(x+4)^2 is x= 3/2

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(x-7)^2=(x+4)^2

(x - 7)^{2} = (x + 4)^{2}

x = \frac{3}{2}

Decimal Notation

x = 1.5

Solution steps

(x - 7)^{2} = (x + 4)^{2}

Expand

(x - 7)^{2} : x^{2} - 14 x + 49

Expand

(x + 4)^{2} : x^{2} + 8 x + 16

x^{2} - 14 x + 49 = x^{2} + 8 x + 16

Move

49

to the right side

x^{2} - 14 x = x^{2} + 8 x - 33

Subtract

x^{2} + 8 x

from both sides

x^{2} - 14 x - (x^{2} + 8 x) = x^{2} + 8 x - 33 - (x^{2} + 8 x)

Simplify

- 22 x = - 33

Divide both sides by

- 22

x = \frac{3}{2}

4 k + 0.5 (2 k - 4) = 6 k - 2 - 8 k

y, 2 x - 3 y = - 15

(y - 6) - (y + 5) = 3 y

x + 0.05 x = 4400

X, X + Y = 4