What is the answer to solvefor x,y^2=9+xz ?

The answer to solvefor x,y^2=9+xz is x=(y^2-9)/z ;\quad z\ne 0

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solvefor x,y^2=9+xz

solve for

x, y^{2} = 9 + x z

x = \frac{y ^{2} - 9}{z}; z \neq = 0

Solution steps

y^{2} = 9 + x z

Switch sides

9 + x z = y^{2}

Move

9

to the right side

x z = y^{2} - 9

Divide both sides by

z; z \neq = 0

x = \frac{y ^{2} - 9}{z}; z \neq = 0

y, 7 x + 5 y = - 35

- (2 x + 8) = - 3 (- x + 1)

y, 12 y - 9 x = - 36

- (- 4 x + 5) = 4 x - 6

60 + \frac{x}{3} = 120

What is the answer to solvefor x,y^2=9+xz ?
The answer to solvefor x,y^2=9+xz is x=(y^2-9)/z ;\quad z\ne 0