What is the answer to q*(a+y(q))=67y(q)+93 ?

The answer to q*(a+y(q))=67y(q)+93 is y=(67y(q)+93)/q-a;\quad q\ne 0

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q*(a+y(q))=67y(q)+93

solve for

y, q \cdot (a + y) = 67 y (q) + 93

y = \frac{67 y ( q ) + 93}{q} - a; q \neq = 0

Solution steps

q (a + y) = 67 y (q) + 93

Divide both sides by

q; q \neq = 0

a + y = \frac{67 y ( q ) + 93}{q}; q \neq = 0

Move

a

to the right side

y = \frac{67 y ( q ) + 93}{q} - a; q \neq = 0

7 = \frac{2}{5} x + 1

y, 5 x - y = 2

3 x - 0.6 = x + 4.4

4

10 - \frac{3 x - 1}{2} = \frac{6 x + 3}{11}

What is the answer to q*(a+y(q))=67y(q)+93 ?
The answer to q*(a+y(q))=67y(q)+93 is y=(67y(q)+93)/q-a;\quad q\ne 0