What are the solutions to the equation v^2-10v+25=0 ?

The solutions to the equation v^2-10v+25=0 are v=5

Find the zeros of v^2-10v+25=0

The zeros of v^2-10v+25=0 are v=5

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v^{2} - 10 v + 25 = 0

v = 5

Solution steps

v^{2} - 10 v + 25 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 25 = 0

v_{1, 2} = \frac{- ( - 10 ) \pm 0}{2 \cdot 1}

v = \frac{- ( - 10 )}{2 \cdot 1}

\frac{- ( - 10 )}{2 \cdot 1} = 5

v = 5

The solution to the quadratic equation is:

v = 5

2 a - 6

(2 - 3 x)^{2} + 2 (x - 1)^{2} = 0

2^{x^{2} + 2 x} < \frac{1}{2}

\frac{3 x ^{3} y ^{4} \cdot 6 x y ^{- 5}}{( 3 x y ) ^{2}}

6 x - 5 = 8 x + 2

What are the solutions to the equation v^2-10v+25=0 ?
The solutions to the equation v^2-10v+25=0 are v=5
Find the zeros of v^2-10v+25=0
The zeros of v^2-10v+25=0 are v=5