What are the solutions to the equation a^2=1 ?

The solutions to the equation a^2=1 are a=1,a=-1

Find the zeros of a^2=1

The zeros of a^2=1 are a=1,a=-1

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a^{2} = 1

a = 1, a = - 1

Solution steps

a^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = 1, a = - 1

1 = 1

- 1 = - 1

a = 1, a = - 1

x + 5 < 6

- 4 - \frac{1}{2}

∣ x - 2 ∣ \leq 4

\frac{4 x - y}{x - y} + \frac{x - 3 y}{y - x}

\frac{7}{10} - \frac{5}{8}

What are the solutions to the equation a^2=1 ?
The solutions to the equation a^2=1 are a=1,a=-1
Find the zeros of a^2=1
The zeros of a^2=1 are a=1,a=-1