What is the answer to solvefor x,y^3-xy=2 ?

The answer to solvefor x,y^3-xy=2 is x=-(2-y^3)/y ;\quad y\ne 0

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solvefor x,y^3-xy=2

solve for

x, y^{3} - x y = 2

x = - \frac{2 - y ^{3}}{y}; y \neq = 0

Solution steps

y^{3} - x y = 2

Move

y^{3}

to the right side

- x y = 2 - y^{3}

Divide both sides by

- y; y \neq = 0

x = - \frac{2 - y ^{3}}{y}; y \neq = 0

y, - 2 x - 4 y = 8

\frac{1}{2} (4 x - 6) = 11

j, q = \frac{j}{n}

A, b = \frac{1}{4} A f

y, 2 y - 2 x = 4

What is the answer to solvefor x,y^3-xy=2 ?
The answer to solvefor x,y^3-xy=2 is x=-(2-y^3)/y ;\quad y\ne 0