What is the answer to roots k^2+7x+10 ?

The answer to roots k^2+7x+10 is x=(-k^2-10)/7

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roots k^2+7x+10

roots

k^{2} + 7 x + 10

x = \frac{- k ^{2} - 10}{7}

Solution steps

k^{2} + 7 x + 10

The roots are the intercepts with the x-axis

(y = 0)

k^{2} + 7 x + 10 = 0

Move

k^{2}

to the right side

7 x + 10 = - k^{2}

Move

10

to the right side

7 x = - k^{2} - 10

Divide both sides by

7

x = \frac{- k ^{2} - 10}{7}

\frac{3}{5} - \frac{1}{7} b = \frac{1}{4}

(x + 6)^{2} = (x - 7)^{2}

x, x - y + z = 0

- 10 n = 40

- 6 x - 21 = 27

What is the answer to roots k^2+7x+10 ?
The answer to roots k^2+7x+10 is x=(-k^2-10)/7