What are the solutions to the equation 2p^2=-8p+3 ?

The solutions to the equation 2p^2=-8p+3 are p=(-4+sqrt(22))/2 ,p=-(4+sqrt(22))/2

Find the zeros of 2p^2=-8p+3

The zeros of 2p^2=-8p+3 are p=(-4+sqrt(22))/2 ,p=-(4+sqrt(22))/2

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2 p^{2} = - 8 p + 3

p = \frac{- 4 + 22}{2}, p = - \frac{4 + 22}{2}

Decimal Notation

p = 0.34520 \dots, p = - 4.34520 \dots

Solution steps

2 p^{2} = - 8 p + 3

Move

3

to the left side

2 p^{2} - 3 = - 8 p

Move

8 p

to the left side

2 p^{2} - 3 + 8 p = 0

Write in the standard form

a x^{2} + b x + c = 0

2 p^{2} + 8 p - 3 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

8^{2} - 4 \cdot 2 (- 3) = 222

p_{1, 2} = \frac{- 8 \pm 2 22}{2 \cdot 2}

Separate the solutions

p_{1} = \frac{- 8 + 2 22}{2 \cdot 2}, p_{2} = \frac{- 8 - 2 22}{2 \cdot 2}

p = \frac{- 8 + 2 22}{2 \cdot 2} : \frac{- 4 + 22}{2}

p = \frac{- 8 - 2 22}{2 \cdot 2} : - \frac{4 + 22}{2}

The solutions to the quadratic equation are:

p = \frac{- 4 + 22}{2}, p = - \frac{4 + 22}{2}

- 18 < - 2 x \leq 8

5.3 x + 2 - 4.1 x = 3.6 x - 1.6

3 x - 7 > 4 x + 2

∣ 9 x ∣ < 36

x^{2} + 3 x + 2 = 0

What are the solutions to the equation 2p^2=-8p+3 ?
The solutions to the equation 2p^2=-8p+3 are p=(-4+sqrt(22))/2 ,p=-(4+sqrt(22))/2
Find the zeros of 2p^2=-8p+3
The zeros of 2p^2=-8p+3 are p=(-4+sqrt(22))/2 ,p=-(4+sqrt(22))/2