What is the answer to x^2=16+(x-4)(x+4) ?

The answer to x^2=16+(x-4)(x+4) is True for all x

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x^2=16+(x-4)(x+4)

x^{2} = 16 + (x - 4) (x + 4)

True for all x

Solution steps

x^{2} = 16 + (x - 4) (x + 4)

Expand

16 + (x - 4) (x + 4) : x^{2}

x^{2} = x^{2}

Move

x^{2}

to the left side

0 = 0

Both sides are equal

True for all x

y, 2 x = e^{y} - e^{- y}

\frac{5 s + 8}{7} = 4

9 x + 20 = 92

- \frac{5}{6} h - \frac{2}{3} h = - 24

\frac{3}{4} - \frac{1}{8} z = \frac{1}{4}

What is the answer to x^2=16+(x-4)(x+4) ?
The answer to x^2=16+(x-4)(x+4) is True for all x
Solve for x: x^2=16+(x-4)(x+4)
The solution is True for all x