What is the answer to solvefor x,n*(17+x)=34x-r ?

The answer to solvefor x,n*(17+x)=34x-r is x=(-r-17n)/(n-34);\quad n\ne 34

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solvefor x,n*(17+x)=34x-r

solve for

x, n \cdot (17 + x) = 34 x - r

x = \frac{- r - 17 n}{n - 34}; n \neq = 34

Solution steps

n (17 + x) = 34 x - r

Expand

n (17 + x) : 17 n + n x

17 n + n x = 34 x - r

Move

17 n

to the right side

n x = 34 x - r - 17 n

Move

34 x

to the left side

n x - 34 x = - r - 17 n

Factor

n x - 34 x : x (n - 34)

x (n - 34) = - r - 17 n

Divide both sides by

n - 34; n \neq = 34

x = \frac{- r - 17 n}{n - 34}; n \neq = 34

y, - 4 x + y = 28

y, 2 x + 5 y = 0

y + 12 = - 26

x, y = f (x - 4)

8 \cdot (2 x - 6) = 128

What is the answer to solvefor x,n*(17+x)=34x-r ?
The answer to solvefor x,n*(17+x)=34x-r is x=(-r-17n)/(n-34);\quad n\ne 34