What is the answer to (x+1)^2+(x-6)^2=2x^2 ?

The answer to (x+1)^2+(x-6)^2=2x^2 is x= 37/10

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(x+1)^2+(x-6)^2=2x^2

(x + 1)^{2} + (x - 6)^{2} = 2 x^{2}

x = \frac{37}{10}

Decimal Notation

x = 3.7

Solution steps

(x + 1)^{2} + (x - 6)^{2} = 2 x^{2}

Expand

(x + 1)^{2} + (x - 6)^{2} : 2 x^{2} - 10 x + 37

2 x^{2} - 10 x + 37 = 2 x^{2}

Move

37

to the right side

2 x^{2} - 10 x = 2 x^{2} - 37

Move

2 x^{2}

to the left side

- 10 x = - 37

Divide both sides by

- 10

x = \frac{37}{10}

y, - 8 x + 4 y = 24

y, - 8 x - 4 y - 64 = 0

48 - 18 x = 9 x + 30

- 0.1 + 1.7 y = 0.9

\frac{6 x + 2}{3} - 2 = \frac{4 x - 4}{6}

What is the answer to (x+1)^2+(x-6)^2=2x^2 ?
The answer to (x+1)^2+(x-6)^2=2x^2 is x= 37/10
Solve for x: (x+1)^2+(x-6)^2=2x^2
The solution is x= 37/10