What is (12m^{-4}p^2)/(-15m^3p^{-9)} ?

The solution to (12m^{-4}p^2)/(-15m^3p^{-9)} is -(4p^{11})/(5m^7)

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simplify (12m^{-4}p^2)/(-15m^3p^{-9)}

simplify

\frac{12 m ^{- 4} p ^{2}}{- 15 m ^{3} p ^{- 9}}

- \frac{4 p ^{11}}{5 m ^{7}}

Solution steps

\frac{12 m ^{- 4} p ^{2}}{- 15 m ^{3} p ^{- 9}}

Factor the number:

12 = 3 \cdot 4

= \frac{3 \cdot 4 m ^{- 4} p ^{2}}{- 15 m ^{3} p ^{- 9}}

Factor the number:

15 = 3 \cdot 5

= \frac{3 \cdot 4 m ^{- 4} p ^{2}}{- 3 \cdot 5 m ^{3} p ^{- 9}}

Cancel the common factor:

3

= \frac{4 m ^{- 4} p ^{2}}{- 5 m ^{3} p ^{- 9}}

Simplify

\frac{p ^{2}}{p ^{- 9}} : p^{11}

= \frac{4 m ^{- 4} p ^{11}}{- 5 m ^{3}}

Simplify

\frac{m ^{- 4}}{m ^{3}} : \frac{1}{m ^{7}}

= \frac{4 p ^{11}}{- 5 m ^{7}}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{4 p ^{11}}{5 m ^{7}}

\frac{- 15}{- 3}

\frac{1}{2} \cdot 4 \cdot 3

\frac{6 ^{7}}{6 ^{5}}

6 x^{2} - 19 x + 3

p^{2} - 6 - q \cdot (p^{2} - 6) 2

What is (12m^{-4}p^2)/(-15m^3p^{-9)} ?
The solution to (12m^{-4}p^2)/(-15m^3p^{-9)} is -(4p^{11})/(5m^7)