What are the solutions to the equation 5x^2+9x=18 ?

The solutions to the equation 5x^2+9x=18 are x= 6/5 ,x=-3

Find the zeros of 5x^2+9x=18

The zeros of 5x^2+9x=18 are x= 6/5 ,x=-3

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5 x^{2} + 9 x = 18

x = \frac{6}{5}, x = - 3

Solution steps

5 x^{2} + 9 x = 18

Move

18

to the left side

5 x^{2} + 9 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 5 ( - 18 )}{2 \cdot 5}

9^{2} - 4 \cdot 5 (- 18) = 21

x_{1, 2} = \frac{- 9 \pm 21}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 9 + 21}{2 \cdot 5}, x_{2} = \frac{- 9 - 21}{2 \cdot 5}

x = \frac{- 9 + 21}{2 \cdot 5} : \frac{6}{5}

x = \frac{- 9 - 21}{2 \cdot 5} : - 3

The solutions to the quadratic equation are:

x = \frac{6}{5}, x = - 3

- 13 \leq - 5 r + 2

(m + n)^{2} + \frac{1}{4} - (m + n)

4 + ∣ t + 2 ∣ < 11

(\frac{2}{3})^{\frac{2}{3}}

80 - 50 x

What are the solutions to the equation 5x^2+9x=18 ?
The solutions to the equation 5x^2+9x=18 are x= 6/5 ,x=-3
Find the zeros of 5x^2+9x=18
The zeros of 5x^2+9x=18 are x= 6/5 ,x=-3