What are the solutions to the equation q^2+2q-15=0 ?

The solutions to the equation q^2+2q-15=0 are q=3,q=-5

Find the zeros of q^2+2q-15=0

The zeros of q^2+2q-15=0 are q=3,q=-5

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q^{2} + 2 q - 15 = 0

q = 3, q = - 5

Solution steps

q^{2} + 2 q - 15 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 15) = 8

q_{1, 2} = \frac{- 2 \pm 8}{2 \cdot 1}

Separate the solutions

q_{1} = \frac{- 2 + 8}{2 \cdot 1}, q_{2} = \frac{- 2 - 8}{2 \cdot 1}

q = \frac{- 2 + 8}{2 \cdot 1} : 3

q = \frac{- 2 - 8}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

q = 3, q = - 5

\frac{π}{3} + \frac{π}{4}

\frac{3}{20} - \frac{9}{16}

8 x^{2} - 14

49 x^{2} = 9

5 = \frac{1}{2}

What are the solutions to the equation q^2+2q-15=0 ?
The solutions to the equation q^2+2q-15=0 are q=3,q=-5
Find the zeros of q^2+2q-15=0
The zeros of q^2+2q-15=0 are q=3,q=-5