What are the solutions to the equation solvefor x,y^2=2p(x)x ?

The solutions to the equation solvefor x,y^2=2p(x)x are x= y/(sqrt(2p)),x=-y/(sqrt(2p));\quad p\ne 0

Find the zeros of solvefor x,y^2=2p(x)x

The zeros of solvefor x,y^2=2p(x)x are x= y/(sqrt(2p)),x=-y/(sqrt(2p));\quad p\ne 0

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solve for

x, y^{2} = 2 p (x) x

x = \frac{y}{2 p}, x = - \frac{y}{2 p}; p \neq = 0

Solution steps

y^{2} = 2 p (x) x

Switch sides

2 p xx = y^{2}

Simplify

2 p x^{2} = y^{2}

Divide both sides by

2 p; p \neq = 0

\frac{2 p x ^{2}}{2 p} = \frac{y ^{2}}{2 p}; p \neq = 0

x^{2} = \frac{y ^{2}}{2 p}; p \neq = 0

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{y ^{2}}{2 p}, x = - \frac{y ^{2}}{2 p}; p \neq = 0

Simplify

\frac{y ^{2}}{2 p} : \frac{y}{2 p}

Simplify

- \frac{y ^{2}}{2 p} : - \frac{y}{2 p}

x = \frac{y}{2 p}, x = - \frac{y}{2 p}; p \neq = 0

y, - 2 x + 3 y = 14

y, - 2 x - 9 y = - 25

\frac{4}{11} x + \frac{1}{4} = \frac{1}{8}

- n = 4

y, 2 y = - 1 x - 8

What are the solutions to the equation solvefor x,y^2=2p(x)x ?
The solutions to the equation solvefor x,y^2=2p(x)x are x= y/(sqrt(2p)),x=-y/(sqrt(2p));\quad p\ne 0
Find the zeros of solvefor x,y^2=2p(x)x
The zeros of solvefor x,y^2=2p(x)x are x= y/(sqrt(2p)),x=-y/(sqrt(2p));\quad p\ne 0